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Differentiaali- ja integraalilaskennan laskin

Laske yhden potenssitermin derivaatta ja integraali.

Johdanto

Calculus Calculator — Find the derivative and integral of a single power term. Enter Coefficient a, Exponent n, x to get an instant, accurate result.

Kaava

For a single term a×xⁿ evaluated at x: derivative (power rule) = a×n×x^(n−1); indefinite integral (power rule) = (a/(n+1))×x^(n+1) + C, both evaluated at the given x.

Vaihe vaiheelta

  1. Enter the Coefficient a.
  2. Enter the Exponent n.
  3. Enter the x.
  4. Click Calculate to see your result instantly.

Käytännön esimerkki

Example: With Coefficient a = 2, Exponent n = 3, x = 2, the Calculus Calculator gives Derivative At X: 24, Derivative Term: 6x^2, Integral At X: 8.

Usein Kysytyt Kysymykset

What if n = −1 for the integral?
The power rule fails at n = −1 (it would require an ln|x| term), so no integral result is returned in that case.
Does this handle multi-term polynomials?
No, this calculates the derivative and integral of a single power term a×xⁿ.
What inputs does the Calculus Calculator need?
You'll need to provide: Coefficient a, Exponent n, x. All fields use sensible defaults, so you can see a working example immediately and then adjust the values to match your own numbers.
How accurate is the Calculus Calculator?
The Calculus Calculator applies the formula exactly as calculated — For a single term a×xⁿ evaluated at x: derivative (power rule) = a×n×x^(n−1); indefinite integral (power rule) = (a/(n+1))×x^(n+1) + C, both evaluated at the given x. — so results are precise for the inputs you provide. Accuracy depends on entering correct, realistic input values.
Is the Calculus Calculator free to use?
Yes, the Calculus Calculator is completely free, requires no signup, and runs instantly in your browser.

Tietoa: Differentiaali- ja integraalilaskennan laskin

The Calculus Calculator uses a real, verifiable formula — For a single term a×xⁿ evaluated at x: derivative (power rule) = a×n×x^(n−1); indefinite integral (power rule) = (a/(n+1))×x^(n+1) + C, both evaluated at the given x. — so results are accurate every time, not an approximation.