CalculatorCast

Calcolatore del teorema di Pitagora

Trova il lato mancante di un triangolo rettangolo.

Introduzione

Pythagorean Theorem Calculator — Solve for a missing side of a right triangle. Enter Leg a, Leg b, Hypotenuse c (leave blank to solve for it) to get an instant, accurate result.

Formula

a² + b² = c². Given the two legs, hypotenuse = √(a²+b²). Given the hypotenuse and one leg, the other leg = √(c²−a²).

Passo dopo passo

  1. Enter the Leg a.
  2. Enter the Leg b.
  3. Enter the Hypotenuse c (leave blank to solve for it).
  4. Click Calculate to see your result instantly.

Esempio pratico

Example: With Leg a = 3, Leg b = 4, the Pythagorean Theorem Calculator gives Hypotenuse: 5.

Domande Frequenti

Does this only work for right triangles?
Yes, the Pythagorean theorem specifically applies to right triangles.
What if the hypotenuse I enter is shorter than a leg?
That's not geometrically possible — the calculation will not return a valid real result.
What inputs does the Pythagorean Theorem Calculator need?
You'll need to provide: Leg a, Leg b, Hypotenuse c (leave blank to solve for it). All fields use sensible defaults, so you can see a working example immediately and then adjust the values to match your own numbers.
How accurate is the Pythagorean Theorem Calculator?
The Pythagorean Theorem Calculator applies the formula exactly as calculated — a² + b² = c². Given the two legs, hypotenuse = √(a²+b²). Given the hypotenuse and one leg, the other leg = √(c²−a²). — so results are precise for the inputs you provide. Accuracy depends on entering correct, realistic input values.
Is the Pythagorean Theorem Calculator free to use?
Yes, the Pythagorean Theorem Calculator is completely free, requires no signup, and runs instantly in your browser.

Informazioni su Calcolatore del teorema di Pitagora

The Pythagorean Theorem Calculator uses a real, verifiable formula — a² + b² = c². Given the two legs, hypotenuse = √(a²+b²). Given the hypotenuse and one leg, the other leg = √(c²−a²). — so results are accurate every time, not an approximation.